g^2+21g=0

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Solution for g^2+21g=0 equation: 



g^2+21g=0

a = 1; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·1·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$


$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*1}=\frac{-42}{2}
=-21
$


$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*1}=\frac{0}{2}
=0
$

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